Working on a test review. This question is throwing me for a loop. Any help, including how to set up drawing, would be greatly appreciated!
Two boats leave a dock together, traveling in courses that are straight lines with a difference of 47deg40min btwn their courses. One boat travels 30.2 kph, the other 42.6 kph. How far apart are the boats after 2 hours?
Thanks for your help!
Two boats leave a dock together, traveling in courses that are straight lines with a difference of 47deg40min btwn their courses. One boat travels 30.2 kph, the other 42.6 kph. How far apart are the boats after 2 hours?
Thanks for your help!
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After 2 hours, Boat 1 has travelled 60.4km and Boat 2 has travelled 85.2 km.
To create the drawing use a protractor to measure an angle of (approximately) 47° 40' with the two legs measuring scale versions of the two distances and then join the two end points to create the third side of the triangle, The length of this 3rd side represents the distance between the two boats.
Let b and c be the two known lengths and a the required length.
Using the Cosine Rule : a² = b² + c² - 2bcCosA
a² = 60.4² + 85.2² - (2 x 60.4 x 85.2 x Cos47° 40') = 3648.16 + 7259.04 - 6931.18 = 3976.02
Then a = √3976.02 = 63.056 km
To create the drawing use a protractor to measure an angle of (approximately) 47° 40' with the two legs measuring scale versions of the two distances and then join the two end points to create the third side of the triangle, The length of this 3rd side represents the distance between the two boats.
Let b and c be the two known lengths and a the required length.
Using the Cosine Rule : a² = b² + c² - 2bcCosA
a² = 60.4² + 85.2² - (2 x 60.4 x 85.2 x Cos47° 40') = 3648.16 + 7259.04 - 6931.18 = 3976.02
Then a = √3976.02 = 63.056 km
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http://answers.yahoo.com/question/index?… try this.