Math help me please!!!
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Math help me please!!!

[From: ] [author: ] [Date: 11-04-24] [Hit: ]
5%)=(1-4.5%)555=0.955*555, each year if 4.5% die, then 95.......

Now spot the pattern. (555-555*4.5%)=(1-4.5%)555=0.955*555, each year if 4.5% die, then 95.5% survive. So the number alive in 1996 is 0.955*555 and in 1997 is 0.955*(0.955*555) and so on. The short hand way to write this is (0.955^x)*555=number alive x years after 1995.

a.)2010-1995=15 years, so 0.955^15*555=514.8 is the number alive in 2010.

b.) we need to find the x when 0.955^x*555=50,
0.955^x=50/555
log(0.955^x)=log(50/555)
x * log0.955=log(50/555)
x=log(50/555)/log0.955
x=52.275

So 52 years after 1995 the population will have declined to 50, meaning in 1995+52=2047.

-
1995: 555
1996: 530.025
1997: 506.173875
1998: 483.396050625
1999: 461.643228346875
2000: 440.869283071265625
2001: 421.030165333058671875
2002: 402.083807893071031640625
2003: 383.990036537882835216796875
2004: 366.710484893678107632041015625
2005: 350.20851307346259278859916992188
2006: 334.44912998515677611311220727539
2007: 319.398919135824721188022157948
2008: 305.02596777471260873456116084034
2009: 291.29979922485054134150590860252
2010: 278.19130825973226698113814271541 (answer to part a: 278)
...
2015: 220.98378852094706264619176548103
...
2020: 165.89034552159031005843154061868
...
2025: 131.77650035774425255904592046379
...
2030: 104.677858087133489696188933095
...
2040: 66.052391049387298597551365812714
2041: 63.080033452164870160661554351142
2042: 60.24143194681745100343178440534
2043: 57.5305675092106657082773541071
2044: 54.94169197129618575140487317228 (Answer to part b: 2044).

-
a) 555(.955)^15 = app. 278

b) 50 = 555(.955)^x
x = app. 52 soooo 1995 + 52 = 2047

-
a 375
b 2020

-
a. 278
b. 2047
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