Natural base problem...is this how to do this

y=.05e^-3x , y=.02

dividing .05/.02, and then working it out...

works out to 115.132 ???

Sorry but I got a different answer

.02 = .05e^-3x
2/5 = e^-3x
log(2/5) = -3x * log(e)
x = log(2/5) / -3
x = 0.3054

.05e^-3x =.02
e^3x = 2.5
3x = ln2.5
x = 0.3054