How do you find the missing length to this right triangle

I need to find the missing leg to this right triangle. The hypotenuse is 4 inches, and one of the legs is 3 inches. What is the measure of the missing leg and how did you get to that answer? Thanks!

Pythagoras' theorem:
a(squared) +b(squared) = c(squared)

c refers to the hypotenuse
this means that if you square both sides and add them up, you get the length of the hypotenuse squared

so,

3(squared) + b(squared) = 4(squared)

9+b(squared) = 16

b(squared) = 7

b = √7


hope i helped :)

In a right triangle, the hypotenuse is 4 inches,
and one of the legs is 3 inches.
The measure of the missing leg is
√(4^2 - 3^2) = √7 = 2.646 inches.

you do 3 squared + b squared= 4 squared
so 9+b=16
then 16-9
so you have 7=b squared
then the square root of 7 is the length of the other leg

That's Pythagorean theorem.

Hint: hypotenuse^2 - leg^2 = other_leg^2 by Pythagoras.

a^2 + b^2 = c^2

3^2 + b^2 = 4^2
9 + b^2 = 16
b^2 = 7
b = √7

the answer is the square root of 7