Make a the subject of the formula
2(3a-c)=5c+1
Thanx :)
2(3a-c)=5c+1
Thanx :)
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2(3a-c)=5c+1
=> 6a - 2c = 5c + 1
=> 6a = 5c + 2c + 1
=> a = ( 5c + 2c + 1 ) / 6
Answer
=> 6a - 2c = 5c + 1
=> 6a = 5c + 2c + 1
=> a = ( 5c + 2c + 1 ) / 6
Answer
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No, the user who said it already is is wrong...
Divide by 2 to get:
3a - c = (5c + 1)/2
Add c to both sides to remove it from the left:
3a = (5c + 1)/2 + c
Divide both sides by c:
a = (5c + 1)/6 + (c/3)
Now a is the subject! Hope it helped!
Divide by 2 to get:
3a - c = (5c + 1)/2
Add c to both sides to remove it from the left:
3a = (5c + 1)/2 + c
Divide both sides by c:
a = (5c + 1)/6 + (c/3)
Now a is the subject! Hope it helped!
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6a - 2c = 5c + 1 Expand the brackets
6a = 7c + 1 Try and get only the subject on the left side
a = (7c+1) / 6 If there's a number in front of the subject then you divide both sides with that number
6a = 7c + 1 Try and get only the subject on the left side
a = (7c+1) / 6 If there's a number in front of the subject then you divide both sides with that number
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Get rid of the brackets 6a - 2c = 5c + 1, therefore 6a = 5c + 2c + 1, therefore 6a = 7c + 1. Divide both sides by 6 (to leave "a" by itself) a = 7c + 1. good luck
6
6
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2(3a-c)=5c+1
3a-c=(5c-1)/2
3a=(5c-1)/2+c
a=( (5c-1)/2+c)/3
3a-c=(5c-1)/2
3a=(5c-1)/2+c
a=( (5c-1)/2+c)/3
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It already is!! sorry!