A motorcycle has four gears. The maximum speed in bottom gear is 40 km h^-1 and the maximum sped in top gear is 120kmh^-1. Given that the maximum speeds in each successive gear form a geometric progression, calculate, in kmh^-1 to on d.p., the maximum speeds in the two intermediate gears.
How does one go about doing this?? Help please...
Thanks!
How does one go about doing this?? Help please...
Thanks!
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Let the common ratio of the geometric sequence be r. You then have maximum speeds of
40, 40*r, 40*r^2, 40*r^3 = 120
Can you finish from there?
40, 40*r, 40*r^2, 40*r^3 = 120
Can you finish from there?