If the angle θ is in the first quadrant, 0 is less than θ which is less than 2, and if cosθ=6, find EXACT values for the following:
cscθ = ?
cotθ = ?
cscθ = ?
cotθ = ?
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First, since θ is in first quadrant, then 0 < θ < π/2
Second there is no real value of θ such that cos(θ) = 6,
since -1 ≤ cos(θ) ≤ 1
Perhaps you want to check that question again.
Second there is no real value of θ such that cos(θ) = 6,
since -1 ≤ cos(θ) ≤ 1
Perhaps you want to check that question again.