A ball is thrown from a 78 meter cliff with an initial velocity (10 m/s), right before the ball is thrown what is the acceleration (magnitude and direction)?
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a physics problem, can u help me with that.
10 points
heeeeeeeeeeeeeeeeeelpppppppppp????
a physics problem, can u help me with that.
10 points
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Before the ball leaves the thrower's hand (attaining the status "is thrown") it is accelerated by his muscle power from 0 up to 10m/s. This happens over a throwing (hand movement) distance of about 1 m. With an initial speed of 0 and a final speed of 10, the average speed over this meter is 5 m/s so the throw takes about 0.2 s making the acceleration during the throw about 10/0.2 = 50m/s². The direction of this acceleration is principally the same as the ball's direction of its immediately subsequent travel.
Don't forget that 10 points!!!
Don't forget that 10 points!!!
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Before the ball is thrown it's velocity and acceleration are zero.
At the instant it begins flight it's acceleration is "g" (9.81m/s²),
and it's velocity will have vertical and horizontal components
such that the vertical component is the sine of the angle above
horizontal, and the horizontal component is the cosine of the
angle above horizontal.
At the instant it begins flight it's acceleration is "g" (9.81m/s²),
and it's velocity will have vertical and horizontal components
such that the vertical component is the sine of the angle above
horizontal, and the horizontal component is the cosine of the
angle above horizontal.