An open cylindrical vessel of height 83 cm and radius 50mm contains fluid of density 1181 kg/m3. how do I calculate the gauge pressure on the base of the vessel, answer in pascals thanks.
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P(gauge) = rho*g*h, where rho is the fluid's density, g is the acceleration due to gravity, and h is the height (or depth) of the fluid column. The width of the fluid column is inconsequential.
P(gauge) = 1181 kg/m³ x 9.81 m/s² x 0.83 m = 9.6x10^3 Pa
I hope that helps. Good luck!
P(gauge) = 1181 kg/m³ x 9.81 m/s² x 0.83 m = 9.6x10^3 Pa
I hope that helps. Good luck!