2 KNO3 → 2 KNO2 + 1 O2 If 500g of potassium nitrate (KNO3) react to completion, how much (KNO2) is produced

2 KNO3 → 2 KNO2 + 1 O2

If 500g of potassium nitrate (KNO3) react to completion, how much potassium nitrite (KNO2) is produced?

No idea how to work this out. I got an answer of 4.945mol KNO2

Convert the 500 g into moles of KNO3

moles = 500 g / 101.11 g/mol = 4.945 moles

Now look at your equation. the mole ratio between KNO3 and KNO2 is 2 to 2 (1 to 1)

So if you use up 4.945 moles of KNO3 then you also produce 4.945 moles of KNO2

Now convert that many moles of KNO2 into a mass

mass = moles x molar mass