What is the pH of a 2.62 x 10 -2 M NaOH solution
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What is the pH of a 2.62 x 10 -2 M NaOH solution

[From: ] [author: ] [Date: 13-05-28] [Hit: ]
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pOH = -log(OH-)
pOH = -log(2.62*10^-2)
pOH = 1.58
pH = 14 - 1.58
pH = 12.42
1
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