Ethanol (C2H5OH) is produced from the fermentation of sucrose in the presence of enzymes.
C12H22O11(aq) + H2O(g) 4 C2H5OH(l) + 4 CO2(g)
Determine the theoretical yield and the percent yields of ethanol if 735 g sucrose undergoes fermentation and 314.5 g ethanol is obtained.
theoretical
g
percent
%
C12H22O11(aq) + H2O(g) 4 C2H5OH(l) + 4 CO2(g)
Determine the theoretical yield and the percent yields of ethanol if 735 g sucrose undergoes fermentation and 314.5 g ethanol is obtained.
theoretical
g
percent
%
-
Theoretical: 395.4 grams
Percent yield: 79.5%
Percent yield: 79.5%
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Avoid dying by not leaving your homework to the last minute, also look at formulae like No. mole =mass/Formula weight and 1 mole sucrose gives you 4 mole ethanol theoretically [in your equation].