A.) (1/2)
B.) 1
C.) 3
D.) 4.5
E.) 5
B.) 1
C.) 3
D.) 4.5
E.) 5
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f(x) = x² + 2/x
f '(x) = 2x - 2/x²
f '(x) is undefined at x = 0
f '(x) = 0 at x = 1
<..-..1..+...>
There is a minimum at x = 1 because f '(x) changes from - to +
f '(x) = 2x - 2/x²
f '(x) is undefined at x = 0
f '(x) = 0 at x = 1
<..-..1..+...>
There is a minimum at x = 1 because f '(x) changes from - to +
-
Yep. SO what is your question?
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