What is the temperature of a .587 moles of a gas that is held in a sealed 4.83 L container at 34.3 psi?
I know that when I convert 34.3 psi to atm, I get 2.3 atm
I know how to do the problem, I just don't know how to set it up.
I know that when I convert 34.3 psi to atm, I get 2.3 atm
I know how to do the problem, I just don't know how to set it up.
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PV = nRT
They gave you all the parameters, now solve for T.
R is a constant. 0.082058 L x atm/(K x mol)
PV / nR = T
2.3(4.73) / 0.587(0.082058) = T
T = 225.86 K
They gave you all the parameters, now solve for T.
R is a constant. 0.082058 L x atm/(K x mol)
PV / nR = T
2.3(4.73) / 0.587(0.082058) = T
T = 225.86 K
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Use PV=nRT so P is the 2.3 atm, V is the 4.73 L, n is the .587 moles, R since your using atm is .082, and T is what your solving for, good luck and i hope i helped.