I'm trying to figure out the net ionic equation for 2CH3CO2H(aq) + Ba(OH)2(aq) --> (CH3CO2)2Ba(aq) + 2H2)(l)
Please explain how you got your answer. Thank you so much!!
Please explain how you got your answer. Thank you so much!!
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The last product of this reaction should be water and not hydrogen.
The reactants contain the following ions:
2H+(aq) and CH3CO2-(aq) from the ethanoic acid solution
Ba2+(aq) and 2OH-(aq) from the barium hydroxide solution
During the reaction the 2H+(aq) ions combine with the 2OH-(aq) ions to form 2H2O(l)
The Ba2+(aq) ions and the CH3CO2-(aq) ions remain unchanged, since barium ethanoate is fully ionised in aqueous solution. They can therefore be left out of the ionic equation.
The net ionic equation, therefore is:
2H+(aq) + 2OH-(aq) ==> 2H2O(l)
The reactants contain the following ions:
2H+(aq) and CH3CO2-(aq) from the ethanoic acid solution
Ba2+(aq) and 2OH-(aq) from the barium hydroxide solution
During the reaction the 2H+(aq) ions combine with the 2OH-(aq) ions to form 2H2O(l)
The Ba2+(aq) ions and the CH3CO2-(aq) ions remain unchanged, since barium ethanoate is fully ionised in aqueous solution. They can therefore be left out of the ionic equation.
The net ionic equation, therefore is:
2H+(aq) + 2OH-(aq) ==> 2H2O(l)
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Ya know what? It says this is wrong.... not sure if there's one tiny thing missing. Anyone notice what's wrong?
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