I was thinking about this:
Step 1.) oxidize the double bond to get CH3COOH
Thanks!
Step 1.) oxidize the double bond to get CH3COOH
Thanks!
-
CH2=CH-CH3 is propene
CH2=CH-CH3 + O3/CH2Cl2 + Zn/H2O ---------> CH3-CHO (ethanal) + CH2O (methanal)
above reaction is ozonolysis ...
CH3-CHO + HCN ---------> CH3-CH(OH)-CN
CH3-CH(OH)-CN + H+/H2O ---------> CH3-CH(OH)-COOH
feel free to ask any question
CH2=CH-CH3 + O3/CH2Cl2 + Zn/H2O ---------> CH3-CHO (ethanal) + CH2O (methanal)
above reaction is ozonolysis ...
CH3-CHO + HCN ---------> CH3-CH(OH)-CN
CH3-CH(OH)-CN + H+/H2O ---------> CH3-CH(OH)-COOH
feel free to ask any question
-
I agree with AS on this one. I was initially thinking of converting the alkene to a glycol using OsO4 and then oxidizing this to the carboxylic acid using CrO3/H2SO4, but this is not a good method because cleavage of the glycol would predominate under these conditions. By the time I had thought of using AS's method, he/she had already answered the question and so deserves best answer. Pulkit's method is wrong in just about every aspect.
-
Step 1:- CH2CHCH3 +HBr(in peroxide)------> CH3CHBrCH3 [anti Markonikov's rule ]
Step 2:-CH3CHBrCH3+KMnO4 (acidic)------->CH3CHBrCooH [strong Oxidation ]
Final Step :- CH3CHBrCooH + KOH---------> CH3CH(OH)COOH
Step 2:-CH3CHBrCH3+KMnO4 (acidic)------->CH3CHBrCooH [strong Oxidation ]
Final Step :- CH3CHBrCooH + KOH---------> CH3CH(OH)COOH