Chemistry help? Please I have a test :'( TMR! It's quick, I promise!

Calculate the concentration of the solute in mol/L in the diluted solution: 25.0mL of 0.22M MgSO4 diluted to 500.0mL

I think the answer is 8.0M but the answer key says 0.0080M, so which answer is right, and if I'm wrong please show me how you got the other answer, thanks SO very much <3

C1V1 = C2V2 If I read the problem right you start with 25 mL of a 0.22 mol/L solution then dilute it to 500 mL?

0.22 x 25 = C2 x 500

C2 is 0.011 mol/L not 0.0080

Um I'm getting a completely different answer from you and your answer key.

use the formula:

M1V1 = M2V2
Im pretty sure you've used this equation before so I won't get into what everything means.

For this equation you can have the units of volume in mL but I'll do it in mL and Liters to show my answer. Ill even do a mole analysis to confirm my answer.

25mL * 0.22M = 500mL * xM
x = 0.011M


25mL = 0.025L
500mL = 0.5L

0.025L * 0.22M = 0.5L * xM
x = 0.011M


Now for the mole analysis.

25mL = 0.025L

Molarity = moles / L

0.22M = xmoles / 0.025L
x = 0.0055moles.

When we dilute this solution to 500mL the moles will stay the same.

500mL = 0.5L

xM = 0.0055moles / 0.5L
x = 0.011M

Each way I did I got the same answer of 0.011M

You should check this problem with your teacher.

Make sure that you are using the proper units for molarity (moles/LITER). I believe you may have accidentally used moles/milliliter, which can easily be converted by three decimal places, giving you your answer of 8.0 M. You likely know what you're doing and simply need to pay attention to units!