Help with aqueous solutions.
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Help with aqueous solutions.

[From: ] [author: ] [Date: 12-05-19] [Hit: ]
Hope this helps!-There is a formula that states the auto-ionization for pure water (Kw) is 1.0e-14. Since Kw=[OH-]x[H+] we can plug in for what you have: 1.0e-14/5.35e3 = 1.......
What is [OH‾] in an aqueous solution at 298 K in which [H+] = 5.35 *10^(3) M.

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To solve this you need to find the pH, then the pOH, and then you can solve for the [OH-]

to find pH, take -log[H+]

then to find pOH, take 14 - pH = pOH (pH + pOH = 14)

then take 10^-pOH

This will get you from [H+] to the [OH-]

Hope this helps!

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There is a formula that states the auto-ionization for pure water (Kw) is 1.0e-14. Since Kw=[OH-]x[H+] we can plug in for what you have: 1.0e-14/5.35e3 = 1.87e-18 = [OH-]
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keywords: aqueous,Help,with,solutions,Help with aqueous solutions.
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