It is necessary to know that this happens at 100 degrees, but that fact doesnt enter into the calculation.......
So would it be (2.3 kj/g) (25g)? What do I do with the 100 degrees celcius? Is it just extra information that is not needed?
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You are correct. It is necessary to know that this happens at 100 degrees, but that fact doesn't enter into the calculation.
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