Percentage composition by mass: 62.0% Carbon, 10.4% Hydrogen, 27.5% Oxygen. Molar mass is 58.1 g/mol. What is the molecular formula?
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Percentage composition by mass: 62.0% Carbon, 10.4% Hydrogen, 27.5% Oxygen. Molar mass is 58.1 g/mol. What is the molecular formula?
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62.0/12 = 5.167 for C
10.4/1.008 = 10.317 for H
27.5/16 = 1.719 for O
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taking oxygen as 1, we have:
5.167/1.719 or 3.006 for carbon
10.317/1.719 or 6.002 for hydrogen
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and so the empirical formula
for the compound is
C3H6O. But since we are given the
atomic weight of 58.1,
and 12x3 + 6x1 + 16 is 58, then C3H6O
is also the molecular formula.
--------------------------------------…
62.0/12 = 5.167 for C
10.4/1.008 = 10.317 for H
27.5/16 = 1.719 for O
---------------------------------
taking oxygen as 1, we have:
5.167/1.719 or 3.006 for carbon
10.317/1.719 or 6.002 for hydrogen
---------------------------
and so the empirical formula
for the compound is
C3H6O. But since we are given the
atomic weight of 58.1,
and 12x3 + 6x1 + 16 is 58, then C3H6O
is also the molecular formula.
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Carbon Hydroxide
-2
CHO
-2
CHO