C6H6+C6H5Br+HBr which of the following changes will cause an increase in the rate of the above rxn

A) increasing the concentration of Br2
B) decreasing the concentration of C6H6
C) increasing the concentration HBr
D) decreasing the temperature

I believe the reaction equation below is correct.
C6H6 + Br2 → C6H5Br + HBr
1281 + 46 = 1327 1248 + 87 = 1335
Increasing the concentration of a reactant will increase the rate of the reaction.
Increasing the concentration of a product will not increase the rate of the reaction.
Br2 and C6H6 are reactants, and HBr is a product.

If the reaction is exothermic, heat energy is released as the reaction occurs. When heat energy is released, decreasing the temperature will increase the rate of the reaction. I checked the bond energies for each compound to determine whether the reaction is exothermic or endothermic.

C6H6 + Br2 → C6H5Br + HBr
1281 + 46 = 1327 1248 + 87 = 1335
Energy released by reaction = Energy of products – Energy of reactants
Since the energy of the products is greater than the energy of the reactants, the reaction is exothermic. So, decreasing the temperature will increase the rate of the reaction.