How to calulate the concentration of an ION
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How to calulate the concentration of an ION

[From: ] [author: ] [Date: 12-04-22] [Hit: ]
-If you want the number of moles,0.005 x0.1 =5x10^-3 x1.......
25ml 0.1 M solution of Ammonium Iron (II) Sulfuric Acid
was titrated by
5ml 0.1 M solution of Potassium Manganate

Moles of Fe(II) = 25ml x 0.1 / 1000
= 0.0025 moles

Moles of MnO4- = 5ml x 0.1 / 1000
= 0.0005 moles


Why is it divided by "1000" to get the concentration of these ions??
If someone can help I would be grateful

-
They are using the formula:

n (number of moles) = c (concentration) x V (volume in cm^3) / 1000

n = c x (V/1000)

Basically, it is divided by 1000 to convert cm^3, to dm^3, which is the SI (from French: Système international d'unités) unit for volume.

1dm^3 is approximately equivalent to 1 litre.

-
If you want the number of moles, just multiply the molarity by the volume in Litres
KmnO4 Moles = M x L
0.005 x0.1 = 5x10^-3 x1.0x10^-1 5x10^-5 moles
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