Also how many moles are from that problem?
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PV = nRT
n = PV / RT = (1.000 atm) x (100.0 L) / ((0.08205746 L atm/ K mol) x (273.15 K)) = 4.461 mol Cl2
(4.461 mol Cl2) x (70.9064 g Cl2/mol) = 316.3 g Cl2
n = PV / RT = (1.000 atm) x (100.0 L) / ((0.08205746 L atm/ K mol) x (273.15 K)) = 4.461 mol Cl2
(4.461 mol Cl2) x (70.9064 g Cl2/mol) = 316.3 g Cl2