When the following reaction is at equilibrium and the volume of the container is decreased,
COCl2(g) = CO(g) + Cl2(g)
A. the forward reaction rate increases.
B. the forward reaction rate decreases.
C. the reverse reaction rate increases.
D. the equilibrium remains unchanged.
COCl2(g) = CO(g) + Cl2(g)
A. the forward reaction rate increases.
B. the forward reaction rate decreases.
C. the reverse reaction rate increases.
D. the equilibrium remains unchanged.
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The answer is B. the forward reaction rate decreases.
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Decreased volume for a gas-phase reaction will shift the system toward the side of the reaction with the fewest moles of gas. Hence the equilibrium shifts towards the left. Whether that means the forward reaction rate decreases or the reverse reaction rate increases, I'll let you figure out.
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B. coz wen vol. Of container is decreased then then fwd rate will decrease coz in this rxn one mole of COCl2 gives one mole of CO n one mole of Cl2 so it means that one mole of reactants gives two moles of products so, wen the vol. is dec. The rxn would prefer the way that vol. Doesnt inc. So the fwd rate dec.