Sulfur dioxide and water react to produce sulfurous acid. If 3 moles of sulfurous acid are produced then
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Sulfur dioxide and water react to produce sulfurous acid. If 3 moles of sulfurous acid are produced then

[From: ] [author: ] [Date: 11-12-27] [Hit: ]
022 x 10^23 particles of that substance.So 3 moles of H2O x 6.022 x 10^23 = 1.81 x 10^23 molecules of H2O are involved in this reaction.......
how many molecules of water were involved in the reaction?

SO2+H2O---> H2SO3

I just want to be able to know how to do this problem. I have no idea.

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Dragon you are wrong. Sulfurous acid is H2SO3 and sulfuric acid is H2SO4 (check wiki links)

The rest of your explanations is good but you made a typo

3 moles of H2O x 6.022 x 10^23 = 1.81 x 10^24 (please note it has to be 10^24)

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Well actually, in the formula you give above you are producing sulfuric acid, not sulfurous acid (HSO3-)
Ignoring that, you know that for every one mole of H2O (water) consumed, 1 moles of H2SO3 is produced. So if 3 moles of H2SO3 were produced then 3 moles of H2O were consumed.
Avagadro's number gives us that for every 1 mole of a substance there are 6.022 x 10^23 particles of that substance.
So 3 moles of H2O x 6.022 x 10^23 = 1.81 x 10^23 molecules of H2O are involved in this reaction.
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