how many molecules of water were involved in the reaction?
SO2+H2O---> H2SO3
I just want to be able to know how to do this problem. I have no idea.
SO2+H2O---> H2SO3
I just want to be able to know how to do this problem. I have no idea.
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Dragon you are wrong. Sulfurous acid is H2SO3 and sulfuric acid is H2SO4 (check wiki links)
The rest of your explanations is good but you made a typo
3 moles of H2O x 6.022 x 10^23 = 1.81 x 10^24 (please note it has to be 10^24)
The rest of your explanations is good but you made a typo
3 moles of H2O x 6.022 x 10^23 = 1.81 x 10^24 (please note it has to be 10^24)
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Well actually, in the formula you give above you are producing sulfuric acid, not sulfurous acid (HSO3-)
Ignoring that, you know that for every one mole of H2O (water) consumed, 1 moles of H2SO3 is produced. So if 3 moles of H2SO3 were produced then 3 moles of H2O were consumed.
Avagadro's number gives us that for every 1 mole of a substance there are 6.022 x 10^23 particles of that substance.
So 3 moles of H2O x 6.022 x 10^23 = 1.81 x 10^23 molecules of H2O are involved in this reaction.
Ignoring that, you know that for every one mole of H2O (water) consumed, 1 moles of H2SO3 is produced. So if 3 moles of H2SO3 were produced then 3 moles of H2O were consumed.
Avagadro's number gives us that for every 1 mole of a substance there are 6.022 x 10^23 particles of that substance.
So 3 moles of H2O x 6.022 x 10^23 = 1.81 x 10^23 molecules of H2O are involved in this reaction.