if light of frequency 1x10^15 s^-1 is used for irradiating the metal. No idea how to do this!
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[ photon energy ] = [ metal work function energy ] + [ KE of electron ejected ]
[ h * f ] = [ 3.43E-19 ] + [ KE ]
[ 6.626 069E-34 * 1E+15 ] = [ 3.43E-19 ] + [ KE ]
KE = 3.196E-19 J <=======ans
[ h * f ] = [ 3.43E-19 ] + [ KE ]
[ 6.626 069E-34 * 1E+15 ] = [ 3.43E-19 ] + [ KE ]
KE = 3.196E-19 J <=======ans