how much heat can be produced if you use 450g of lead in the following reaction:
Pb + 2Cl2 ---> PbCl4 ΔH = -330 KJ
Pb + 2Cl2 ---> PbCl4 ΔH = -330 KJ
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Divide 450 g between the molecular weight of the Lead... that will the moles of lead!
Notice that -330 KJ is the heat produced by a mole of lead under that reaction...
Now, simply multiply the moles you get and the heat...
And that's your answer!
Notice that -330 KJ is the heat produced by a mole of lead under that reaction...
Now, simply multiply the moles you get and the heat...
And that's your answer!