For the reaction NH4Br(s) -> NH3(g) + HBr(g), why is the change of "n" = 2
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For the reaction NH4Br(s) -> NH3(g) + HBr(g), why is the change of "n" = 2

[From: ] [author: ] [Date: 11-05-16] [Hit: ]
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The equation used is:
Kp = Kc(RT)^change of n

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In these problems "n" refers to the moles of gases present. Since the reactant is a solid and both products are gases, change in n = 2 - 0 = 2

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Because the reactant is a solid (n = 0) and there are 2 moles of gas in the product (n = 2).
∴ ∆n = 2 – 0 = 2

The equation you're cited is easy to derive:
Kp = P(NH₃) • P(HBr) = {n(NH₃)RT/V} • {n(HBr)RT/V} = {n(NH₃)/V}•{n(HBr)/V}•(RT)²
= [NH₃][HBr]•(RT)² = Kc •(RT)²
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