If you dilute a strong acid with water, will the pH of the solution rise or remain the same

If it rises no explanation is needed but if it stays the same could you pleases explain why.
Thanks in advance,
Fergus

It would increase.

The strong acid is already in aqueous solution, and thus has already dissociated completely. When you add water, you are increasing the volume of the solution, but you are not increasing the number of moles of H+ ions in solution.
Thus, according to the molar relationship (Concentration = moles/volume), the concentration of H+ ions would decrease due to an increase in volume)
Since pH = -log [H+], decreasing the value of H+ would cause an increase to the pH.

Assuming you are taking the pH of the water. The pH of the water would LOWER. The H+ concentration would rise.

If you are trying to take the pH of the strong acid (which is very difficult) the pH would rise, because the total H+ concentration is diminished. It would take a swimming pool of water to get the pH of the strong acid to 6.9999

The pH of neutral water is 7. Acids are less than 7 (typically 0-6) bases are greater than 7 (typically 8-14).

It rises because it reduces the concentration of the H+ ions.

The pH of a .01 molar acid is 2, whereas the pH of a .5 molar acid is .301. The diluted solution has a higher pH than the .5 molar solution.

Remains the same as the pH of water is neutral.