10mL of propanoic acid (Ka=5.5x10^-5) is titrated with 25mL of KOH (0.2M) to the equivalence point..
Favorites|Homepage
Subscriptions | sitemap
HOME > Chemistry > 10mL of propanoic acid (Ka=5.5x10^-5) is titrated with 25mL of KOH (0.2M) to the equivalence point..

10mL of propanoic acid (Ka=5.5x10^-5) is titrated with 25mL of KOH (0.2M) to the equivalence point..

[From: ] [author: ] [Date: 11-04-22] [Hit: ]
Ka would only be needed if you needed to know the pH at the equivalence point, which is not 7.......
10mL of an unknown concentration of propanoic acid (Ka=5.5x10^-5) is titrated with 25mL of KOH (0.2M) to the equivalence point. What is the concentration of propanoic acid?

-
The Ka is not needed; the equivalence point occurs when the numbers of moles of acid equals the number of moles of base. Since propanoic acid is monoprotic, the equation is:

MaVa = MbVb
Ma = 0.2 M * 25 mL / 10 mL = 0.5 M

Ka would only be needed if you needed to know the pH at the equivalence point, which is not 7.

-
I mean equivalenve point

Report Abuse

1
keywords: the,of,5.5,with,is,mL,titrated,KOH,point,0.2,to,10,25,acid,equivalence,Ka,propanoic,10mL of propanoic acid (Ka=5.5x10^-5) is titrated with 25mL of KOH (0.2M) to the equivalence point..
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .