PART 1)
One reaction that produces hydrogen gas can be represented by the unbalanced chemical equation
Mg(s) + HCl(aq) -----> MgCl2(aq) + H2 (g)
What mass of HCl is consumed by the reaction of 3.64 mol of magnesium? Answer in units of g please!
If you could answer part two and part three too that'd be great! Thanks!!!
PART 2)
What mass of MgCl2 is produced? Answer in units of g please!
PART 3)
What mass of H2 is produced? Answer in units of g please!
Thank you so much!
One reaction that produces hydrogen gas can be represented by the unbalanced chemical equation
Mg(s) + HCl(aq) -----> MgCl2(aq) + H2 (g)
What mass of HCl is consumed by the reaction of 3.64 mol of magnesium? Answer in units of g please!
If you could answer part two and part three too that'd be great! Thanks!!!
PART 2)
What mass of MgCl2 is produced? Answer in units of g please!
PART 3)
What mass of H2 is produced? Answer in units of g please!
Thank you so much!
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Balance the equation:
Mg + 2HCl --> MgCl2 + H2
Note that 1 mole of Mg consumes 2 mole of HCl and produces 1 mole of MgCl2 and 1 mole of H2.
Moles of HCl = 2 x 3.64 moles of Mg = 7.28 moles of HCl
Moles of MgCl2 = 1 x 3.64 moles of Mg = 3.64 moles of MgCl2
Moles of H2 = 1 x 3.64 moles of Mg = 3.64 moles of H2
7.28 moles of HCl x 36.46 g/mole = 265 g HCl
3.64 moles of MgCl2 x 95.22 g/mole = 347 g MgCl2
3.64 moles of H2 x 2.016 g/mole = 7.34 g H2
Mg + 2HCl --> MgCl2 + H2
Note that 1 mole of Mg consumes 2 mole of HCl and produces 1 mole of MgCl2 and 1 mole of H2.
Moles of HCl = 2 x 3.64 moles of Mg = 7.28 moles of HCl
Moles of MgCl2 = 1 x 3.64 moles of Mg = 3.64 moles of MgCl2
Moles of H2 = 1 x 3.64 moles of Mg = 3.64 moles of H2
7.28 moles of HCl x 36.46 g/mole = 265 g HCl
3.64 moles of MgCl2 x 95.22 g/mole = 347 g MgCl2
3.64 moles of H2 x 2.016 g/mole = 7.34 g H2