Pure water is saturated with PbCl2. In this saturated solution:
1. [Pb2+] = [Cl−]
2. [Pb2+] [Cl−] = Ksp
3. 2 [Cl−] = [Pb2+]
4. Ksp = [Pb2+]
5. [Pb2+] = 0.5 [Cl−]
**the answer is definitely not choice 3!
1. [Pb2+] = [Cl−]
2. [Pb2+] [Cl−] = Ksp
3. 2 [Cl−] = [Pb2+]
4. Ksp = [Pb2+]
5. [Pb2+] = 0.5 [Cl−]
**the answer is definitely not choice 3!
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for this dissolution..
AxBy ----> xA + yB
Ksp = [A]^x [B]^y
so...for this problem...
Ksp = [Pb+2] x [Cl-]²
as to the choices..
(1) is incorrect.. there are 2 Cl's for every 1 Pb.. ie.. [Cl-] = 2 x [Pb+2]
(2) is incorrect..
(3) is incorrect
(4) is incorrect..
(5) is correct... concentration Pb = 1/2 the concentration of Cl..because 1 PbCl2 ---> 1 Pb + 2 Cl
AxBy ----> xA + yB
Ksp = [A]^x [B]^y
so...for this problem...
Ksp = [Pb+2] x [Cl-]²
as to the choices..
(1) is incorrect.. there are 2 Cl's for every 1 Pb.. ie.. [Cl-] = 2 x [Pb+2]
(2) is incorrect..
(3) is incorrect
(4) is incorrect..
(5) is correct... concentration Pb = 1/2 the concentration of Cl..because 1 PbCl2 ---> 1 Pb + 2 Cl
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The answer is (5) - there will be half as many lead ions as there are chlorine ions.