What is the minimum amount of 6.1 M H2SO4 necessary to produce 25.1 g of H2 (g) according to the following reaction:
2 Al (s) + 3 H2SO4 (aq) --> Al2(SO4)3 (aq) + 3 H2 (g)
2 Al (s) + 3 H2SO4 (aq) --> Al2(SO4)3 (aq) + 3 H2 (g)
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use molecular mass to find moles of H2
25.1/.503975 =12.7
use stoichiometric ratio of H2 and H2SO4 to find moles of H2SO4
12.7 * 3/3 or 12.7 * 1 = 12.7
use concentration (M) to find liters of H2SO4 needed
12.7/6.1 = 2.08
25.1/.503975 =12.7
use stoichiometric ratio of H2 and H2SO4 to find moles of H2SO4
12.7 * 3/3 or 12.7 * 1 = 12.7
use concentration (M) to find liters of H2SO4 needed
12.7/6.1 = 2.08