If 5 grams of CO and 5 grams of O2 are combined according to the reaction 2CO + O2(arrow)2CO2, which is the limiting reagent?
CO2
O2
CO
CO and O2
CO2
O2
CO
CO and O2
-
One person gave no explanation and the other... well, I got lost.
2CO + O2 --> 2CO2
5g ...... 5g
Do a "what if". If 5 g of CO reacts, what mass of O2 will react?
5 g CO x (1 mol CO / 28 g CO) x (1 mol O2 / 2 mol CO) x (32 g O2 / 1 mol O2) = 2.86 g O2
Since there is more O2 than you need, it is in excess and CO is the limiting reactant.
When all five grams of the CO has been used up, only 2.86 grams of the O2 will be used, leaving excess O2.
2CO + O2 --> 2CO2
5g ...... 5g
Do a "what if". If 5 g of CO reacts, what mass of O2 will react?
5 g CO x (1 mol CO / 28 g CO) x (1 mol O2 / 2 mol CO) x (32 g O2 / 1 mol O2) = 2.86 g O2
Since there is more O2 than you need, it is in excess and CO is the limiting reactant.
When all five grams of the CO has been used up, only 2.86 grams of the O2 will be used, leaving excess O2.
-
CO is the Limiting reagaent
2CO2 + O2 -> 2CO2
n ( CO )= m/ M n( O2) = m/M
n = 5g/ M( 12+ 16) n = 5g/ M( 16*2)
n (CO) = O .17857mols n ( O2) = 0.625mols
But the ratio says 2 mols of CO reacts with 1 mols of O2
so we devide n( CO) by the ration 1mol(O2)/ 2mol(CO)
SO... n(CO)= 0.17857 * 1/2 = 0.089285mol
The ratio is now even and we can say 0.089285mol of CO will reacting with 0.625mol of O2
To determine the LR which amount of mols is smaller??
CO is with 0.089285mol reacting , so CO is the LR
Hope this makes sense =)
2CO2 + O2 -> 2CO2
n ( CO )= m/ M n( O2) = m/M
n = 5g/ M( 12+ 16) n = 5g/ M( 16*2)
n (CO) = O .17857mols n ( O2) = 0.625mols
But the ratio says 2 mols of CO reacts with 1 mols of O2
so we devide n( CO) by the ration 1mol(O2)/ 2mol(CO)
SO... n(CO)= 0.17857 * 1/2 = 0.089285mol
The ratio is now even and we can say 0.089285mol of CO will reacting with 0.625mol of O2
To determine the LR which amount of mols is smaller??
CO is with 0.089285mol reacting , so CO is the LR
Hope this makes sense =)
-
CO is the limiting reagent. Since, moles of CO and O2 are in the ratio 2: 1, from the given data, we get the ratio as 1.41: 1