sorry, i would redo it but i want to sleep... so bye
bye the way, i looked at the guy who answered before i, and not that i dont think he knows what he is doing, but it seems to me that he made a mistake way in the beginning. I don't see how it is possible how each equilibrium concentration is less than the original. since it shifts left as he and i both agree upon, the equilibrium concentrations on the left have to increase. also he has like two division things. (again, not to insult him... i mean it in the most respectable way possible)
okay, i know that i said that i needed sleep, but i changed my mind. i used an online calculator thing to solve for x for me and i got x=0.002788811 and 0.01289229 but 0.01289229 cant be the answer because .015-2*.01289229 < 0. so let's look at the things again:
[Br2]=.055+x= .057788811
[BrCl]= .0150-2x= .009422378
[Cl2]= .085 + x = .087788811
Check:
Kc= (.009422378^2)/(.087788811*.057788811)=0…
hell yeah!!!! that matches the Kc from the problem. BOO YA!!! Yea so those are the answers!! See how important it is to check your work. :) I thank you for this problem because it got me critically thinking (except when i used the online calculator thing lol) anyway... i hope you were able to follow my madness through all of that . if you are confused, the equation that i put into the online calculator was
.0175= [(.015-2x)^2]/[(.085+x)(.055+x)] i dont think that i specified that. And from there i got the x values and was able to solve.
I did take one more look at the other guy's answers and they do plug back in to almost the same Kc but they are not as accurate as this response and also im still pretty sure that he didnt go about it correctly. I think that his results are not horrible because the numbers are so small that the changes don't carry much weight, but for a future test, make sure that you are using the proper method.