I have a trouble with Punnet Square for the combination of two genes in fruit fly on
two different chromosome pairs. One gene diminutive with a symbol dn is on the X-chromosome (chromosome 1), it has a recessive allele dn- that results in smaller body size
when homozygous. dn+ is the wildtype designation. The other gene Curly, symbol Cu,
dominantly affects wing shape and is on an autosome. Cu- mutants have curly wings. Cu- is
also homozygous lethal. In the cross, the female is heterozygous at both genes. The male is
heterozygous for Curly alleles and is hemizygous for dn+
. draw an “X” over the lethal genotypes.
two different chromosome pairs. One gene diminutive with a symbol dn is on the X-chromosome (chromosome 1), it has a recessive allele dn- that results in smaller body size
when homozygous. dn+ is the wildtype designation. The other gene Curly, symbol Cu,
dominantly affects wing shape and is on an autosome. Cu- mutants have curly wings. Cu- is
also homozygous lethal. In the cross, the female is heterozygous at both genes. The male is
heterozygous for Curly alleles and is hemizygous for dn+
. draw an “X” over the lethal genotypes.
-
In this case you would need to do a larger punnet cross. Since they are on TWO different chromosome pairs, it's entirely possible that you can have any combination of the genes. SO... your punnet parents would be....
Female X Male
dn+/dn-;Cu/Cu- X dn+;Cu/Cu-
Female potential combinations
dn+;Cu
dn+;Cu-
dn-;Cu
dn-;Cu-
Male potential combinations
dn+;Cu
dn+:cu-
When you cross these, those that have the homozygous lethal genotypes are the ones you want to X over.
Female X Male
dn+/dn-;Cu/Cu- X dn+;Cu/Cu-
Female potential combinations
dn+;Cu
dn+;Cu-
dn-;Cu
dn-;Cu-
Male potential combinations
dn+;Cu
dn+:cu-
When you cross these, those that have the homozygous lethal genotypes are the ones you want to X over.