2 forces are applied to a box of 8.0 kg; one is of 5.0 N towards the North. THe other is of 8.0 N towards the West. Determine the magnitude of the acceleration? Need formula!
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AS THE VECTORS CANNOT BE ADDED BY GENERAL ALGEBRA.
Therefore, you have to find the net force.
Since, the forces are perpendicular
Hence, Angle=90 degees
Net Force F= sqrt(F1^2 + F2^2+ F1.F2. Cos(90) )
a= F/m
Therefore, you have to find the net force.
Since, the forces are perpendicular
Hence, Angle=90 degees
Net Force F= sqrt(F1^2 + F2^2+ F1.F2. Cos(90) )
a= F/m
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As one force is towards north and other is towards west, net force will be in north-west direction.
net force = square root(f1^2+f2^2) = square root ( 5^2 +8^2) = square root (89)
and F=mass*acceleration => acceleration = Force/mass = square root (89)/8.
net force = square root(f1^2+f2^2) = square root ( 5^2 +8^2) = square root (89)
and F=mass*acceleration => acceleration = Force/mass = square root (89)/8.
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Assuming no friction:
Net applied force = sqrt.(8^2 + 5^2) = 9.434N.
Acceleration = (f/m) = 9.434/8, = 1.179m/sec^2.
Net applied force = sqrt.(8^2 + 5^2) = 9.434N.
Acceleration = (f/m) = 9.434/8, = 1.179m/sec^2.