Numerical in physics on work energy power
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Numerical in physics on work energy power

[From: ] [author: ] [Date: 12-07-14] [Hit: ]
i didnt understand how to include mass in the formula P=E/A-Hello captaincool07, first let us make ourselves clear about the concepts of work,We need energy to perform work. So work performed will be equal to the energy spent provided no loss in doing the work.But power is the rate at which the work is done or energy spent.Now the question has to be Which student has more power?......
Two physics students, Will N. Andable and Ben Pumpiniron, are in the weightlifting room. Will lifts the 100-pound barbell over his head 10 times in one minute; Ben lifts the 100-pound barbell over his head 10 times in 10 seconds. Which student does the most work?
please help
i didn't understand how to include mass in the formula P=E/A

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Hello captaincool07, first let us make ourselves clear about the concepts of work, energy and power
We need energy to perform work. So work performed will be equal to the energy spent provided no loss in doing the work.
So energy and work would have the same unit joule (J)
But power is the rate at which the work is done or energy spent.
So its unit will be J/s or watt (W)
Now the question has to be " Which student has more power?"
Both do the same amount of work provided both lift the bell to the same height right from the ground level
But Will does it in 60 seconds but Ben does it just within 10 seconds.
So Ben is six times powerful than Will.
Because power = work / time
Work is the same. Power is inversely related to the time duration. So more time less power and less time more power. Hence Ben is the most powerful.
If you would like know about the work performed then we use the formula Mg h. M- mass of the bar bell, h- height through which it has been lifted. g - acceleration due to gravity.

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They both do the same amount of work. The only difference is the time frame.
Not sure about the formula
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