Two charged particles, q1 = −2.50×10−3 C and q2 = +3.850e-3 C, are separated by a distance of 5.00 cm. (a) What is the electric potential energy of this configuration? (b) What is the electric potential at a point midway between the particles?
Thank You!
Thank You!
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(a).
dW = F dr
dW = kQq/r² dr
. . . . r
W = ∫ kQq/r² dr
. . . ∞
W = -kQq/r
W = -(9 * 10^9)(-2.50 * 10^-3)(3.85 * 10^-3)/0.05
W = 1.7325 * 10^6 Joule
(b).
V = V1 + V2
V = kQ/r + kq/r
V = k(Q + q)/r
V = (9 * 10^9)(-2.50 * 10^-3 + 3.85 * 10^-3)/(½ * 0.05)
V = 486000000 volt
dW = F dr
dW = kQq/r² dr
. . . . r
W = ∫ kQq/r² dr
. . . ∞
W = -kQq/r
W = -(9 * 10^9)(-2.50 * 10^-3)(3.85 * 10^-3)/0.05
W = 1.7325 * 10^6 Joule
(b).
V = V1 + V2
V = kQ/r + kq/r
V = k(Q + q)/r
V = (9 * 10^9)(-2.50 * 10^-3 + 3.85 * 10^-3)/(½ * 0.05)
V = 486000000 volt