What is the magnitude and direction of the tack's angular velocity vector if the vehicle is traveling at 10.0 km/h?
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(10 km/h)(1000/3600) = 2.78 m/s
r = 0.648/2 = 0.324 m
ω = v/r = (2.78)/(0.324) = 8.58 rad/s
r = 0.648/2 = 0.324 m
ω = v/r = (2.78)/(0.324) = 8.58 rad/s