The period T of a simple pendulum is described by T= (2pi)*square root(l/g). Show that this equation gives the correct unit for the period.
Thank you.
Thank you.
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The variables with units in the equation are:
l = length, unit = m (metres)
g = accel due to gravity, unit = m/s^2 (metres per second-squared)
l / g has units of m / m/s^2 = s^2 (seconds squared)
So sqrt(l / g) has units of sqrt (s^2) = s (seconds)
which is the correct unit for the period time T.
l = length, unit = m (metres)
g = accel due to gravity, unit = m/s^2 (metres per second-squared)
l / g has units of m / m/s^2 = s^2 (seconds squared)
So sqrt(l / g) has units of sqrt (s^2) = s (seconds)
which is the correct unit for the period time T.