a particle is moving in a plane with a velocity given by -
U = u i^(i cap) + wa cos(wt) j^ (w=omega and a =accelaration)
. the particle is at the origin at t=0. the trajectory of the particle is?
a)y = a sin(wu/x)
b)y = a sin (wx/u)
c)y = a cos(wu/x)
d)y = a cos (wx/u)
hint - answer is option B. Can someone please help me out?
thanks
U = u i^(i cap) + wa cos(wt) j^ (w=omega and a =accelaration)
. the particle is at the origin at t=0. the trajectory of the particle is?
a)y = a sin(wu/x)
b)y = a sin (wx/u)
c)y = a cos(wu/x)
d)y = a cos (wx/u)
hint - answer is option B. Can someone please help me out?
thanks
-
The velocity in the y direction is given as ωa cos ωt
dy /dt = ωa cos ωt
Integrating
y = a sin ωt + C
Using the condition that y = 0 when t = 0
C = 0
Hence y = a sin ωt
================================
From dx/dt = u
dx = u dt
Integrating x = ut + c
Using the condition that x = 0 when t = 0
x = ut and hence t = x/u
y = a sin ωt = a sin (wx/u)
hence the answer is b) y = a sin (wx/u)
C = 0
Hence the answer is y = a sin ωt
dy /dt = ωa cos ωt
Integrating
y = a sin ωt + C
Using the condition that y = 0 when t = 0
C = 0
Hence y = a sin ωt
================================
From dx/dt = u
dx = u dt
Integrating x = ut + c
Using the condition that x = 0 when t = 0
x = ut and hence t = x/u
y = a sin ωt = a sin (wx/u)
hence the answer is b) y = a sin (wx/u)
C = 0
Hence the answer is y = a sin ωt