Algebra 1 help please??? 10 pts! :)

1. Write the equation for the vertical line passing through (5, 8).
A. x = 5
B. x = 8
C. x = 0
D. x = 5/8

2.Write the equation y - 4 = -2(x - 5) in slope-intercept form.
A. y = -2x + 14
B. y = -2x + 5
C. y = -2x + 9
D. y = -2x + 6

3. Write the point-slope form of the equation passing through (5, -1) with a slope of 6.
A. y-1=6(x+5)
B. y+5=6(x-1)
C. y+1=6(x-5)
D. y-5=6(x+1)

4.If you are finding the line perpendicular to x + 3y = 5, what is the slope of the line?
A. -3/5
B. 1/3
C. 3
D. -3

5.
Write the slope-intercept equation of the line perpendicular to y = 5/2 x - 2, which passes though the point (0, 2).
A. y = 5x + 2
B. y = -2/5x + 2
C. y = 2x + 5
D. y = 1/2x + 5

6. Write the equation for the horizontal line passing through (4, -6).
A. y = 4
B. y = -6
C. y = 4/6
D. y = -6/4

7. Write the slope-intercept form of the equation parallel to y = 7x + 2, which passes through the point (1, -3).
A. y = 7x - 10
B. y = -1/7 x + 2
C. y = 7x - 3
D. y = -7x + 10

8. Write the equation y - 2 = 2(x - 3) in standard form.
A. y - 2x = 4
B. 2x - y = -6
C. 2x + y = 6
D. 2x - y = 4

1. A
why: VUXHOY- Vertical Undefined (slope) X Horizontal 0 (slope) Y
2. A again
why: Foil method -2*x= -2x -2*-5=+10. Then add the 4
3.C (guessing)
4 is C
get Y by itself so y=-(x/3)+5, then the perpendicular slope is the negative reciprocal.
5 is B
Negative reciprocal of the slope, then plug in points
6. B (VUXHOY again)
7. A
why: Parallel lines keep the same slope, so plug in 1*7 and you get 7, y needs to be -3, so -10 is new intercept.
8. D (Foil)