Write the parametric equations in the given caretsian form

x=3t-t^3, y=5-2t

x=?

help please!

the same idea like in your previous question:

x=3t-t³
y=5-2t
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y=5-2t
2t=5-y
t=(5-y)/2

x=3t-t³

x=3(5-y)/2 -[(5-y)/2]³

x=(5-y)/2 [ 3 -(5-y)²/4]

y = 5 - 2t
2t = 5 - y
t = (1/2) * (5 - y)

x = 3t - t^3
x = 3 * (1/2) * (5 - y) - (1/2)^3 * (5 - y)^3
x = (1/2) * (5 - y) * (3 - (1/2)^2 * (5 - y)^2)
x = (1/2) * (5 - y) * (3 - (1/4) * (25 - 10y + y^2))
x = (1/2) * (5 - y) * (1/4) * (12 - 25 + 10y - y^2)
x = (1/8) * (5 - y) * (-13 + 10y - y^2)
x = (1/8) * (y - 5) * (y^2 - 10y + 13)