solve for a
ln(A)=-2.78
ln(A)=-2.78
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raise everything to the power of e
e^ and ln are inverse operations and will cancel each other out
ln(A) = -2.78
e^(ln (A) = e^(- 2.78)
A = e^(-2.78)
A = 0.0620
e^ and ln are inverse operations and will cancel each other out
ln(A) = -2.78
e^(ln (A) = e^(- 2.78)
A = e^(-2.78)
A = 0.0620
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ln(a)=-2.78
eˡⁿ⁽ᵃ ⁾= e⁻²·⁷⁸
a =0.0620385074
There ya go!
alice
eˡⁿ⁽ᵃ ⁾= e⁻²·⁷⁸
a =0.0620385074
There ya go!
alice
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You just have to figure out what In or "A" means. Then divide -2.78 over the number.
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ln(A) = B means that e^B = A
So e^-2.78 is about 0.0620385074
So e^-2.78 is about 0.0620385074