what are the numbers?
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The difference between two numbers is 80
x - y = 80
One number is 9 times the other is
x = 9 y
So substitute the x into the first equation and solve for y, then multiply this result by 9 to find x.
9 y - y = 80
8y = 80
y = 10
So x = 9y = 90.
x - y = 80
One number is 9 times the other is
x = 9 y
So substitute the x into the first equation and solve for y, then multiply this result by 9 to find x.
9 y - y = 80
8y = 80
y = 10
So x = 9y = 90.
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let x & y be the numbers.....
given that
x - y = 80--------(1)
also given
x = 9y-----------(2)
substitute (2) in (1)
9y - y = 80
y = 10
substitute in (2)
x = 90
therefore 90 and 10 are the answers
...............☺
given that
x - y = 80--------(1)
also given
x = 9y-----------(2)
substitute (2) in (1)
9y - y = 80
y = 10
substitute in (2)
x = 90
therefore 90 and 10 are the answers
...............☺
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Assume x is the larger number, y is the smaller.
x - y = 80
x = 9y
So
9y - y = 80
8y = 80
y = 10
x = 9y
x = 9(10)
x = 90
Done.
x - y = 80
x = 9y
So
9y - y = 80
8y = 80
y = 10
x = 9y
x = 9(10)
x = 90
Done.
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let one number is x
so the other number is 9x
according to question 9x-x=80
=> 8x=80
=> x=10
so the two numbers are 10, and 90
so the other number is 9x
according to question 9x-x=80
=> 8x=80
=> x=10
so the two numbers are 10, and 90