If a fair coin is flipped 400 times, the probability that fewer than 180 heads are obtained is approximately equal to
a. 0.0228 b. 0.0000 c. 0.4207 d. 0.0793 e. 0. 0456
I know the answer is a, but I just can't seem to figure out how to get the answer, if anyone could help me out, it's much appreciated!
a. 0.0228 b. 0.0000 c. 0.4207 d. 0.0793 e. 0. 0456
I know the answer is a, but I just can't seem to figure out how to get the answer, if anyone could help me out, it's much appreciated!
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You have a binomial distribution with n = 400, p = 0.5, and q = 1 - p = 0.5. The mean of the distribution is
µ = np = 200
The standard deviation is
σ = √(npq) = √100 = 10
If we use the normal approximation to the binomial, then the z score for 180 is
z = (x - µ)/σ = (180 - 200)/10 = -2
From a normal distribution table we find that
p(z < -2) = 0.0228
So the answer is a)
The exact answer using the binomial distribution is 0.0201. The question asked for the approximate answer.
µ = np = 200
The standard deviation is
σ = √(npq) = √100 = 10
If we use the normal approximation to the binomial, then the z score for 180 is
z = (x - µ)/σ = (180 - 200)/10 = -2
From a normal distribution table we find that
p(z < -2) = 0.0228
So the answer is a)
The exact answer using the binomial distribution is 0.0201. The question asked for the approximate answer.
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You'll want a calculator that can do a cumulative binomial distribution. You could also always use excel. You need to add (400Cn)*(.5^n)*(.5^(400-n)) from 0 to 179. When I used excel I got the answer to be 0.02011537. a is the closest answer to the answer that I got. None of the results I got matched your possibilities
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No you have a 50 50 chance for it to land on heads and tails