In the movie, The Attack of the 50 Foot Woman (1993), Daryl Hannah plays a woman who becomes a giant after an encounter with an UFO. Daryl Hannah is 5'10" tall in real life.
a) By what scale factor was Daryl Hannah's height increased in this movie?
b) If her costar husband was 6' tall in real life, how tall would he be by this scale factor? Express your answer in feet and inches (to the nearest inch)
PLEASE EXPLAIN!!!!
a) By what scale factor was Daryl Hannah's height increased in this movie?
b) If her costar husband was 6' tall in real life, how tall would he be by this scale factor? Express your answer in feet and inches (to the nearest inch)
PLEASE EXPLAIN!!!!
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It's just ratios. 50 feet = 50x12 (12 inches in a foot.)
So that's 600 inches.
SHe's really 5 and 10/12 feet tall, so that's 70 inches. Set the ratio
600:70 which simplifies to 60:7 ratio or 60/7:1 ratio
Do the math for the husband.
He's 6 feet so thats 6x12 = 72 60/7:1 so multiply 72 by 60/7
He would be about 617 inches tall or 51"5 inch
So that's 600 inches.
SHe's really 5 and 10/12 feet tall, so that's 70 inches. Set the ratio
600:70 which simplifies to 60:7 ratio or 60/7:1 ratio
Do the math for the husband.
He's 6 feet so thats 6x12 = 72 60/7:1 so multiply 72 by 60/7
He would be about 617 inches tall or 51"5 inch
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50 feet = 50 * 12 = 600 inches
5'10" = 5*12 + 10 = 70 inches
600:70 = 8.57 : 1
You get the idea.
5'10" = 5*12 + 10 = 70 inches
600:70 = 8.57 : 1
You get the idea.
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5.83/50
1:8.57
6(8.57)=51.46=>51'5.5"
1:8.57
6(8.57)=51.46=>51'5.5"