Here is the question,
At the park is a circular wading pool 20 ft in diameter. If parents are seated on the edge of the pool about every 3 ft, how many parents are sitting on the edge of the pool?
At the park is a circular wading pool 20 ft in diameter. If parents are seated on the edge of the pool about every 3 ft, how many parents are sitting on the edge of the pool?
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You need to find the circumference of the pool. The equation for that is 2*pi*radius.
Radius is half of diameter, so it's 10 ft.
2*pi*10ft
We'll just say that pi is 22/7 for simplicities sake.
2*(22/7)*10ft
Circumference is 62.86 feet. (Roughly)
That means there are either 20 or 21 parents. (More 21 than 20)
Radius is half of diameter, so it's 10 ft.
2*pi*10ft
We'll just say that pi is 22/7 for simplicities sake.
2*(22/7)*10ft
Circumference is 62.86 feet. (Roughly)
That means there are either 20 or 21 parents. (More 21 than 20)
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Circumference of pool = pi * diameter = 20pi ft
20 pi divided by 3 = approximately 21 sets of parents
20 pi divided by 3 = approximately 21 sets of parents
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first, find the diameter.
that is 20*pi which is approximately 63.
divide by 3 to get 21 as your answer
that is 20*pi which is approximately 63.
divide by 3 to get 21 as your answer