Engineering mechanics statics questions involving reactions....

A force P of magnitude 450N is applied to member AB which is supported by a frictionless pin at A and by the cable BDC. Since the cable passes over a pulley at D, the tension may be assumed to be the same in the portions BD and CD of the cable. Determine (a) the tension in the cable, (b) the reaction at A when a = 60mm.

Here is a link to a picture Ive drawn to match up with the homework problem. Any help is appreciated.

http://tinypic.com/r/dfwowx/7

FAY = 900N (downwards)
FAX =600 N (rightward)

TDC= 510 N

No member forces or tension can be larger than P!

θ = arctan{160/300} = 28°

→+ ΣFx = 0
-Fax + Tsin28° = 0

↑+ ΣFy = 0
Fay -450 + Tcos28° = 0

ccw+ ΣM@a = 0

0.12T - 0.06*450 = 0, T = 0.06*450/0.12 = 225 N

Fax = Tsin28 = 225*0.4695 = 105.63 N
Fay = 450 - Tcos28 = 450 - 225*0.8829 = 251.3 N

Report Abuse